Question

Sara selects two cards at random from a standard deck of 52 cards. Which of the following could be used to calculate the probability that she will select two numbered cards if she replaces the first card before selecting the second? Note: For this problem, face cards and aces are not numbered cards.

36/52 * 35/51

36/52 * 35/52

36 / 52 * 36/52

36/52 * 36/51

Answer 1

how many numbered cards are there in one deck of 52 cards?

Answer 2

do you mean answer 2 or "two numbered cards"?

Answer 3

yes, i m really confuse all the time :( thats y

Answer 4

the probability she choses a numbered card first is 36/52 since there are 36 numbered cards in a deck. now since she puts that card back in the deck before chosing the second card, the probability stays the same so you just multiply 36/52 by 36/52

Answer 5

ok 2 :(

Answer 6

I know, i m really dumbe

Answer 7

2 cards

Answer 8

There are 13 cards in each "suit", like hearts, spades, diamonds, and clubs. 13 cards each in 4 suits makes 52 total.

In each suit, the cards are 2-10, Jack ,Queen, King, and Ace. The problem says to treat Jack, Queen, King, and Ace as not numbered cards. So there are only 13-4 = 9 numbered cards per suit. With 4 suits, there are 4 x 9 = 36 total numbered cards in the deck.

Answer 9

First try... choose one card.... your chance of getting a numbered card is 36 numbered cards divided by 52 total cards, or 36/52. then you put that card back.

2nd try, same thing... still 36 numbered cards, still 52 total cards, making your chance 36/52.

All together, the chance of getting a numbered card on BOTH tries is the product of the two individual chances, or (36/52) * (36/52)

Answer 10

Thank you so so much guys for helping me!!! :) you all are truly amazing!!!!!!! Love you all :)

Answer 11

Glad to help :) Does it make better sense now?

Answer 12

Yes :) it help alot :) thank u