Question

Please help me!!!!
solve the system using elimination

x+ y + +z =1
2x-y+2x=-5
-x+2y-z = 4

Answer 1

[1 1 1 1]
[2 -1 2 -5]
[-1 2 -1 4]

Set up matrix

Answer 2

i have to use elimination

Answer 3

Good luck with that

Answer 4

i am so confused on how to do these can someone please help!!!

Answer 5

x+ y +z =1
2x-y+2z=-5
-x+2y-z = 4

x + y+z=1
-x+2y-z=4
3y = 5

2x-y+2z=-5
(-x+2y-z=4)2
-2x -4y-2z = 8
-5y = 3

3y = 5
-5y = 3
-2y = 8
y = -4
^^^that's your the y part of the ordered triplet, now you just need to find the x and z values

Answer 6

thanks sooooooooo...... much

Answer 7

could you help me with one more?

Answer 8

x+ y + +z =1
2x-y+2x=-5
-x+2y-z = 4

x+ y +z =1
2x-y+2z=-5
3x+3z =-4

(2x-y+2z=-5)2
4x-2y+4z=-10
-x+2y-z = 4
3x+3z=-6

3x+3z=-4
(3x+3z=-6)-1
-3x-3z=6
0 does not equal 2, so there is no solution for the problem