A satellite is in a circular orbit 29000 km
above the Earth’s surface; i.e., it moves on a
circular path under the inﬂuence of nothing
but the Earth’s gravity.
Find the speed of the satellite. The radius
of the Earth is 6.37 × 10
6 m, and the acceleration of gravity at the satellite’s altitude is
0.318952 m/s
2
.

Question

A satellite is in a circular orbit 29000 km
above the Earth’s surface; i.e., it moves on a
circular path under the inﬂuence of nothing
but the Earth’s gravity.
Find the speed of the satellite. The radius
of the Earth is 6.37 × 10
6 m, and the acceleration of gravity at the satellite’s altitude is
0.318952 m/s
2
.

anonymous · Answer

$$M*V^2/R=M*a $$$$R=r+h$$$$V=\sqrt{a(r+h)}=\sqrt{0.319*(2.9+6.37)*10^6}=1.72*10^3 m/s$$