Use the Comparison theorem to determine whether the integral is convergent or divergent

$$\huge \int \limits_0^1 \frac{sec^2 x}{x\sqrt x}dx$$

Question

Use the Comparison theorem to determine whether the integral is convergent or divergent

$$\huge \int \limits_0^1 \frac{sec^2 x}{x\sqrt x}dx$$

lgbasallote · Answer

my question is....what's the Comparison Theorem?

anonymous · Answer

Find a (simpler) function (to integrate) that upper bounds the integrand (the term inside the integration) and see wether that integral of the new function converges or not...if it does..then your original integration converges too..

lgbasallote · Answer

any function? as long as the limits are same?

anonymous · Answer

yes

lgbasallote · Answer

ahh that would be sufficient information. thanks

anonymous · Answer

but for divergence ...you need yo find a lower bound

anonymous · Answer

i mean to prove divergence ... you need to find a lower bound of the integrand function