Mathematics
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OpenStudy (anonymous):
locate the absolute extrema of the given function on the indicated interval.
f(x)=2(3-x) interval [-1,2]
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OpenStudy (saifoo.khan):
Lol.
OpenStudy (anonymous):
could use a little help!
OpenStudy (anonymous):
3 because it is with the x not before it or after it but with the problem
OpenStudy (saifoo.khan):
Are you sure the equation is correct?
OpenStudy (anonymous):
JK i just guessed...
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OpenStudy (anonymous):
yes, i'm sure
OpenStudy (anonymous):
r u positive it seems off
OpenStudy (anonymous):
there may be no absolute
OpenStudy (saifoo.khan):
Because technically, it's a straight line!
OpenStudy (anonymous):
yes, i understand it is. but i don't know what to do
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OpenStudy (anonymous):
-.- well i cant help u there let that indian dude help u
OpenStudy (saifoo.khan):
#NotIndian. -_-
OpenStudy (anonymous):
i looked in the back of my book and it said the answer was minimum: (2,2) maximum: (-1,8). i just don't know how they get it
OpenStudy (saifoo.khan):
@satellite73
OpenStudy (anonymous):
OOOOOH!
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OpenStudy (anonymous):
oh yay satellite is here :D
OpenStudy (anonymous):
it is a line with a negative slope
biggest at the left hand endpoint
smallest at the right
even the indian dude knows that !
OpenStudy (anonymous):
LMFAO
OpenStudy (anonymous):
|dw:1350610671671:dw|
OpenStudy (saifoo.khan):
|dw:1350610720697:dw|
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OpenStudy (anonymous):
lol! yes, i understand it's a line. i just don't know how to locate the absolute extrema!
OpenStudy (anonymous):
\[f(x)=6-2x\] on \([-1,2]\)largest is
\[f(-1)=8\] smallest is \(f(2)=2\)
OpenStudy (anonymous):
@qtexpress101 it is only on the interval \([-1,2]\) and since the slope is negative, it is largest at the left, smallest at the right
that is all
OpenStudy (saifoo.khan):
Elaborate please.
@satellite73
OpenStudy (anonymous):
woah that guys a genius
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OpenStudy (anonymous):
max is therefore 8, min is 2
don't forget this line does not go on forever, it only exists on that one interval
OpenStudy (saifoo.khan):
guy's *
OpenStudy (omnomnom):
yes he is O_O
OpenStudy (anonymous):
saifoo is the genius, i am just the bengali side kick
OpenStudy (saifoo.khan):
How will you graph this? @satellite73
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OpenStudy (anonymous):
i just did
OpenStudy (anonymous):
so for these type of equations i just distribute or find the derivative then plug in the intervals i am given?
OpenStudy (saifoo.khan):
lol.
OpenStudy (anonymous):
noob
OpenStudy (saifoo.khan):
Oh! Now i get this.
We had to do nothing in this problem.
Stupid question makers just twist the words. -_-
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OpenStudy (anonymous):
|dw:1350610931124:dw|
OpenStudy (anonymous):
no, there was not too much to this one was there?
OpenStudy (anonymous):
nope. i guess i can say, derp.
OpenStudy (saifoo.khan):
NOOB = None Of Our Business.
OpenStudy (anonymous):
so for this example: f(x)= (2x+5)/3 interval [0,5] i find the derivative?
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OpenStudy (saifoo.khan):
No. Just insert the values and get max and min.
OpenStudy (omnomnom):
xD lol saifoo
OpenStudy (saifoo.khan):
If you open up the equation, it will look like:
\[f(x) = \frac23x + \frac53\]
OpenStudy (anonymous):
cool story bro what chapter do u shut up
OpenStudy (saifoo.khan):
Last chapter. Unfortunately you have to read the whole book.
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OpenStudy (omnomnom):
xD lololololol
OpenStudy (anonymous):
interesting unless i nvr start reading the book and shove it down your throat instead... -.-
OpenStudy (omnomnom):
O.O
OpenStudy (anonymous):
COME AT ME BRO!!! i will deck u in the face with a 22.
OpenStudy (omnomnom):
O_O dark.. i think you should stop... O_O
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OpenStudy (saifoo.khan):
Unfortunately, it's an e-book. You can't shove it anywhere. WIN!
OpenStudy (saifoo.khan):
And, nah. I have better things to do than coming at you.