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Mathematics 15 Online
OpenStudy (anonymous):

locate the absolute extrema of the given function on the indicated interval. f(x)=2(3-x) interval [-1,2]

OpenStudy (saifoo.khan):

Lol.

OpenStudy (anonymous):

could use a little help!

OpenStudy (anonymous):

3 because it is with the x not before it or after it but with the problem

OpenStudy (saifoo.khan):

Are you sure the equation is correct?

OpenStudy (anonymous):

JK i just guessed...

OpenStudy (anonymous):

yes, i'm sure

OpenStudy (anonymous):

r u positive it seems off

OpenStudy (anonymous):

there may be no absolute

OpenStudy (saifoo.khan):

Because technically, it's a straight line!

OpenStudy (anonymous):

yes, i understand it is. but i don't know what to do

OpenStudy (anonymous):

-.- well i cant help u there let that indian dude help u

OpenStudy (saifoo.khan):

#NotIndian. -_-

OpenStudy (anonymous):

i looked in the back of my book and it said the answer was minimum: (2,2) maximum: (-1,8). i just don't know how they get it

OpenStudy (saifoo.khan):

@satellite73

OpenStudy (anonymous):

OOOOOH!

OpenStudy (anonymous):

oh yay satellite is here :D

OpenStudy (anonymous):

it is a line with a negative slope biggest at the left hand endpoint smallest at the right even the indian dude knows that !

OpenStudy (anonymous):

LMFAO

OpenStudy (anonymous):

|dw:1350610671671:dw|

OpenStudy (saifoo.khan):

|dw:1350610720697:dw|

OpenStudy (anonymous):

lol! yes, i understand it's a line. i just don't know how to locate the absolute extrema!

OpenStudy (anonymous):

\[f(x)=6-2x\] on \([-1,2]\)largest is \[f(-1)=8\] smallest is \(f(2)=2\)

OpenStudy (anonymous):

@qtexpress101 it is only on the interval \([-1,2]\) and since the slope is negative, it is largest at the left, smallest at the right that is all

OpenStudy (saifoo.khan):

Elaborate please. @satellite73

OpenStudy (anonymous):

woah that guys a genius

OpenStudy (anonymous):

max is therefore 8, min is 2 don't forget this line does not go on forever, it only exists on that one interval

OpenStudy (saifoo.khan):

guy's *

OpenStudy (omnomnom):

yes he is O_O

OpenStudy (anonymous):

saifoo is the genius, i am just the bengali side kick

OpenStudy (saifoo.khan):

How will you graph this? @satellite73

OpenStudy (anonymous):

i just did

OpenStudy (anonymous):

so for these type of equations i just distribute or find the derivative then plug in the intervals i am given?

OpenStudy (saifoo.khan):

lol.

OpenStudy (anonymous):

noob

OpenStudy (saifoo.khan):

Oh! Now i get this. We had to do nothing in this problem. Stupid question makers just twist the words. -_-

OpenStudy (anonymous):

|dw:1350610931124:dw|

OpenStudy (anonymous):

no, there was not too much to this one was there?

OpenStudy (anonymous):

nope. i guess i can say, derp.

OpenStudy (saifoo.khan):

NOOB = None Of Our Business.

OpenStudy (anonymous):

so for this example: f(x)= (2x+5)/3 interval [0,5] i find the derivative?

OpenStudy (saifoo.khan):

No. Just insert the values and get max and min.

OpenStudy (omnomnom):

xD lol saifoo

OpenStudy (saifoo.khan):

If you open up the equation, it will look like: \[f(x) = \frac23x + \frac53\]

OpenStudy (anonymous):

cool story bro what chapter do u shut up

OpenStudy (saifoo.khan):

Last chapter. Unfortunately you have to read the whole book.

OpenStudy (omnomnom):

xD lololololol

OpenStudy (anonymous):

interesting unless i nvr start reading the book and shove it down your throat instead... -.-

OpenStudy (omnomnom):

O.O

OpenStudy (anonymous):

COME AT ME BRO!!! i will deck u in the face with a 22.

OpenStudy (omnomnom):

O_O dark.. i think you should stop... O_O

OpenStudy (saifoo.khan):

Unfortunately, it's an e-book. You can't shove it anywhere. WIN!

OpenStudy (saifoo.khan):

And, nah. I have better things to do than coming at you.

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