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OpenStudy (anonymous):
HELP PLEASE What is the range of the following function?
y=1/x+2 -1
A.{y:y ER, y ≠ -1}
B. {y:y ER, y ≠ 2}
C. {y:y ER}
D. {y:y ER, y ≠ 1}
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OpenStudy (anonymous):
what is ER?
OpenStudy (anonymous):
this
OpenStudy (anonymous):
ooooh i see \(y\in \mathbb{R}\) i get it !
OpenStudy (anonymous):
how do you do it?
OpenStudy (anonymous):
is it
\[f(x)=\frac{1}{x+2}-1\]?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
The range of a function is where the y-coordinate exists. Is the equation \[y =\frac{ 1 }{ x+2 } - 1\]?
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
then we can think
it is pretty clear that
\[\frac{1}{x+2}\] is never zero, because the numerator is 1
OpenStudy (anonymous):
and since
\[\frac{1}{x+2}\] is never zero, then
\[\frac{1}{x+2}-1\] is never \( -1\)
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OpenStudy (anonymous):
so A?
OpenStudy (anonymous):
so i would go with
\[\{y:y\in \mathbb{R}, y\neq -1\}\]
OpenStudy (anonymous):
which i have to say is a rather weird way to write this
we pretty much assume that \(y\) is a real number to start with
OpenStudy (anonymous):
Thanks it was :)
OpenStudy (anonymous):
to answer, yes, A
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OpenStudy (anonymous):
For the record, satellite, that is the correct way to write it on all AP Math tests.
OpenStudy (anonymous):
why not
\[\{y\in \mathbb{R}:y\neq -1\}\] that looks at least half way normal
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