Question

Find the domain of each function f(x)=1-e^(x^2)/1-e^(1-x^2)

Answer 1

is your denominator
\[1-e^{1-x^2}\]?

Answer 2

if so, set
\[1-e^{1-x^2}=0\] and solve for \(x\) you get
\[e^{1-x^2}=1\] making
\[1-x^2=0\] and so \[(1+x)(1-x)=0\]
solve for \(x\) and say all real numbers except those

Answer 3

hope the second step was clear,
only way \(e^{\text{something}}=1\) is if \(\text{something}=0\)

Answer 4

yes it is.

Answer 5

ok good, so you have the answer right? and the method is ok?

Answer 6

How would I put it in interval notation.. (-inf,-1)U(1,inf)?

Answer 7

oh no you missed the part in between

Answer 8

:/ uh oh lol

Answer 9

\[(-\infty, -1)\cup (-1,1)\cup (1,\infty)\] which is a pretty damn long winded way of saying everything except -1 and 1

Answer 10

I was close, okay thanks! :)