Question

how do I solve this equation: logcuberoot(x^2+21x) = 2/3?

Answer 1

\[\log \sqrt[3]{x ^{2}+21x} = 2/3\]

Answer 2

a good idea is to change to exponential form first...

Answer 3

Do you know the definition of log?\[\log_a b = c \implies a^c =b\]

Answer 4

yes

Answer 5

Logarithms are exponents, so the 2/3 is the exponent on the base of the logarithm to get the power cuberoot(x^2+21x)

Answer 6

Hint: This can be rewritten as 3x^2+63x-2=0. Can this be solved using the quadratic equation?

Answer 7

oops i did not see the log.

Answer 8

Hint: power rule then 10^2