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Show that ¬[∃xA(x)] is equivalent to ∀x[¬A(x)]
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\[\neg[\exists xA(x)]\]\[\quad\downarrow\]\[\neg[\exists x]\neg[A(x)]\]\[\quad\downarrow\]\[\forall x [\neg A(x)]\]
is this the way to solve this problem /
Looks right to me. The negation of ∃ is ∀ and then you distributed the negation to A(x).
@joemath314159, @swissgirl , @lgbasallote , @ParthKohli
Yeah, that's right.
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how would you know @ParthKohli
Because you have distributed the negation.
is there any other possible intermediate steps?
I don't see any.
ok cool
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