Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (unklerhaukus):

Show that ¬[∃xA(x)] is equivalent to ∀x[¬A(x)]

OpenStudy (unklerhaukus):

\[\neg[\exists xA(x)]\]\[\quad\downarrow\]\[\neg[\exists x]\neg[A(x)]\]\[\quad\downarrow\]\[\forall x [\neg A(x)]\]

OpenStudy (unklerhaukus):

is this the way to solve this problem /

OpenStudy (anonymous):

Looks right to me. The negation of ∃ is ∀ and then you distributed the negation to A(x).

OpenStudy (unklerhaukus):

@joemath314159, @swissgirl , @lgbasallote , @ParthKohli

Parth (parthkohli):

Yeah, that's right.

OpenStudy (unklerhaukus):

how would you know @ParthKohli

Parth (parthkohli):

Because you have distributed the negation.

OpenStudy (unklerhaukus):

is there any other possible intermediate steps?

Parth (parthkohli):

I don't see any.

OpenStudy (unklerhaukus):

ok cool

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!