evaluate without a calculator: cot(tan^-1 (1/2))
first evaluate tan^-1(1/2) to evaluate an inverse trig function like this you ask yourself, the tangent of what is equal to 1/2?
so tan(x) = 1/2
yes
how do i find that?
|dw:1350628938385:dw| if you notice, you see you'll have to find the value of cosx
ok, so sin(x) = sqrt of 3/1
nopes..recheck..
cos (x) = sqrt 3 / 2
sqrt 5
yes,,it'll be sqrt 5.. now cosx = 2/sqrt5 and hence your ans.
of the whole thing?
Remember, cotangent is Adjacent/Opposite while tangent is Opposite/Adjacent. By doing one and then the other, you're really just flip-flopping the fraction! No need to get crazy here with the math.
oh yea... dur check this out \[ \tan^{-1} (\sqrt{3}) = \pi / 3\] \[\cot(\pi / 3) = \frac{ 1 }{ \sqrt{3} }\] just flipped it... thanks Kainui!
Another way to look at it is that cot(x)=1/tan(x) so you can really just say this problem is doing: \[\frac{ 1 }{ \tan(\tan^{-1}(x)) }\]
So yeah, you don't really have to plug this one into a calculator lol.
Join our real-time social learning platform and learn together with your friends!