Question

Solve for x using factoring and zero product property:
y=x^2-x-12
PLEASE HELP!

Answer 1

solve for x ???
as in isolate the x in this equation???

Answer 2

or do you mean to find the zeros of \(\large y=x^2-x-12 \) ???

Answer 3

yes the second one

Answer 4

ok... so we need to solve: \(\large 0 = x^2-x-12 \)

Answer 5

yes.

Answer 6

notice that: \(\large x^2-x-12=(x-4)(x+3) \)
so the equation becomes: \(\large 0=(x-4)(x+3) \)

isn't it obvious what x needs to be for this equation to hold true?

Answer 7

ummm yes?

Answer 8

so what should x = ???

Answer 9

7??

Answer 10

let's see... x=7
\(\large 0=(\color {red}7-4)(\color {red}7+3) \)

is this a true statement?

Answer 11

I have no idea anymore, I'm confused ...

Answer 12

\(\large 0=(\color {red}7-4)(\color {red}7+3) \)
\(\large 0=(3)(10) \)
\(\large 0=30 \)

is this a true statement?

Answer 13

yes.

Answer 14

???

Answer 15

zero is never equal to 30...
the answer is no.

Answer 16

Oh

Answer 17

Either one of the factors must be 0.