An electron travels at a speed of 3.58x10^6 m/s horizontally to the east. If it travels in a magnetic field of 1.3 T directed vertically upward, determine the magnitude and direction of the magnetic force exerted on the electron.
qvB is the magnitude... direction you find from the right hand rule... fingers point along v rotate your hand so you can curl your fingers to point up your thumb then points in the direction of the force
and don't forget cross vector identity
@gerryliyana tell us about cross vector identity, why don't you.
I don't know what cross vector identity is... What do I cross?
I wouldn't worry about it. Master the right hand rule.
\[v*B\] direction of this will give you the direction of motion of electron
to the left?
i think perpendicular to v and B ...you can figure that out
Yeah, I got to the left. v *b.
no, i think it's incorrect
|dw:1350907553942:dw| look at this ...motion in the perpendicular direction of v and B plane
Oh.. So it's up?
it's not up, already your magnetic field is upwards..it's outta that plane
Oh got you!
so which direction @sexygal ?
out of the page.
|dw:1350908094962:dw| remember it could be in negative direction too which means in to the page ..be careful
Oh yeah electrons are negative, into the page.
take your note pad and draw a little axes on it labeled E N W S E should be the +x direction. put the pad on your lap. draw an arrow pointing east. that's velocity. lay your right hand on the pad so your fingers point along the arrow (East)...
now rotate your hand so that you can curl or fold or point your fingers upwards...
which way does your thumb point?
out of the page
upwards you mean?
yeah.
not possible...
try again, follow the steps.
Down.
South.
so the force is south... IF the quantity qvB is positive... if it's negative, as it happens to be in this case, (because, as you pointed out, q is negative) then you reverse the direction 180 degrees... so South -> North.
the force on the electron points North.
So the magnitude is 4.24 X10^-24. and the direction is north?
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