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Mathematics 8 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

it is convergent?

OpenStudy (anonymous):

looks like a geometric series. what's the r for this series?

OpenStudy (anonymous):

divide a term by the previous term to find r. see if r satisfies the condition for a convergent geometric series.

OpenStudy (anonymous):

The r is -0.03703703703

OpenStudy (anonymous):

(-1/9)/(1/3) = -.037.... ?

OpenStudy (anonymous):

so its a convergent.

OpenStudy (anonymous):

because if r is less than 1 is convergent and if r is greater than 1 and has no limit..it is a divergent

OpenStudy (anonymous):

you should probably find the ratio accurately first. It will be useful in other problems. (1/9)/(-1/3) = ...?

OpenStudy (anonymous):

it equals = -0.33

OpenStudy (anonymous):

you're right about that second part... but r isn't -.037037...

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so yes, convergent because |-1/3| <1

OpenStudy (anonymous):

I had one last q..can you check im wrong? 1/6 + 1/6^2 + 1/6^3 + 1/6^4 ^ this is a divergent

OpenStudy (anonymous):

what's the ratio?

OpenStudy (anonymous):

the ratio is 0.138888

OpenStudy (anonymous):

i subtracted 1/6 - 1/36

OpenStudy (anonymous):

Is that how you find the ratio?

OpenStudy (anonymous):

(1/6) / (1/36)

OpenStudy (anonymous):

(1/36)/(1/6)

OpenStudy (anonymous):

0.166

OpenStudy (anonymous):

so it is not a divergent

OpenStudy (anonymous):

convergent, yes.

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