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OpenStudy (anonymous):
.
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OpenStudy (anonymous):
it is convergent?
OpenStudy (anonymous):
looks like a geometric series. what's the r for this series?
OpenStudy (anonymous):
divide a term by the previous term to find r.
see if r satisfies the condition for a convergent geometric series.
OpenStudy (anonymous):
The r is -0.03703703703
OpenStudy (anonymous):
(-1/9)/(1/3) = -.037.... ?
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OpenStudy (anonymous):
so its a convergent.
OpenStudy (anonymous):
because if r is less than 1 is convergent and if r is greater than 1 and has no limit..it is a divergent
OpenStudy (anonymous):
you should probably find the ratio accurately first. It will be useful in other problems.
(1/9)/(-1/3) = ...?
OpenStudy (anonymous):
it equals = -0.33
OpenStudy (anonymous):
you're right about that second part... but r isn't -.037037...
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so yes, convergent because |-1/3| <1
OpenStudy (anonymous):
I had one last q..can you check im wrong?
1/6 + 1/6^2 + 1/6^3 + 1/6^4
^ this is a divergent
OpenStudy (anonymous):
what's the ratio?
OpenStudy (anonymous):
the ratio is 0.138888
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OpenStudy (anonymous):
i subtracted 1/6 - 1/36
OpenStudy (anonymous):
Is that how you find the ratio?
OpenStudy (anonymous):
(1/6) / (1/36)
OpenStudy (anonymous):
(1/36)/(1/6)
OpenStudy (anonymous):
0.166
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OpenStudy (anonymous):
so it is not a divergent
OpenStudy (anonymous):
convergent, yes.
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