Is 0.001 decimal converted to binary just 1?

Question

anonymous · Answer

Thats what I get when I type it into my calculator on my computer but when I do it from an online converter I get: 
"0.00000000010000011000100100110111"

anonymous · Answer

Well, no. Because floating point representation is complex.

anonymous · Answer

oh ok.

anonymous · Answer

Integer conversion back and forth, however, is very easy.

anonymous · Answer

So neither answer is correct? I'm only asking because I'm trying to convert this decimal into a binary and then hex.

anonymous · Answer

Yeesh, yes the answer is very complex and not easy to answer whatsoever. 

There are several standards for different sizes of floating point numbers. Lookup IEEE 754

amistre64 · Answer

binary$$...2^3 2^2 2^1 2^0 . 2^{-1} 2^{-2} 2^{-3}...$$
$$.5~.25~.125~.0626~...$$it will be some addition of those that add up to .001

amistre64 · Answer

.0625 that is :)

anonymous · Answer

@qpHalcy0n ok I'll do that. 
@amistre64 Alright I guessed I would have to do something like that.

amistre64 · Answer

14/2 = 7 R0
7/2 = 3 R1
3/2 = 1 R1
1/2 = 0 R1

14 = 1110

hmm, i was trying to see if it was as simple as dividing off 2s but that doesnt seem plausible

in any case, it should still amount to some set of the fracionals

anonymous · Answer

I know when I tried solving this originally I multiplied by 2 and started to get the long answer I got above in quotes.

amistre64 · Answer

http://www.wolframalpha.com/input/?i=convert+.001+to+base+2 oy that gives me a headache

anonymous · Answer

@qpHalcy0n 

I've looked up that information and it explains that the first bit is the sign bit (0), the next 8 numbers is the exponent field (00000000) and the fractional part is the remaining digits from 0-23 (100000110001001001101110). 
So when I multiplied .001 by 2 32-times I got the following: $$0.00000000010000011000100100110111$$
now when I typed this into the converter they got : "01110101" for the exponent. This throws off my hexadecimal value by two excluding the zeros from my exponential field I got "83126E" which is wrong according to the converter "3A83126E". Do you know how they are getting the 3 and the A?