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Mathematics 4 Online
OpenStudy (anonymous):

What is the formula for finding out how many possible combinations of ABCDE can be made?

OpenStudy (cwrw238):

= 5!

OpenStudy (anonymous):

I think your question meant to ask how many permutations, not combinations. Combinations do not admit of any order and are just collections. In permutations, you care about the order of the elements.

OpenStudy (cwrw238):

yes 5! is called factorial 5 = 5*4*3*2*1

OpenStudy (anonymous):

5 can't be correct; ABCDE, BCDEA, CDEAB, DEABC, EABCD, ACDEB, ...that's six combos right there and I know there are more

OpenStudy (cwrw238):

which is = 120

OpenStudy (cwrw238):

no: 120 is correct

OpenStudy (anonymous):

I see

OpenStudy (anonymous):

Thank you

OpenStudy (cwrw238):

yw

OpenStudy (anonymous):

The reason why you get 5!, which is as cwrc correctly pointed out, is that you can select any of 5 for the first position, after which you have 4 to select for the 2nd position, after which ther are 3 for the 3rd, etc.

OpenStudy (anonymous):

Thanks I had no idea ! Was a math symbol. Lol I just thought someone was super excited to answer 5

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