What is the formula for finding out how many possible combinations of ABCDE can be made?
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OpenStudy (cwrw238):
= 5!
OpenStudy (anonymous):
I think your question meant to ask how many permutations, not combinations. Combinations do not admit of any order and are just collections. In permutations, you care about the order of the elements.
OpenStudy (cwrw238):
yes
5! is called factorial 5
= 5*4*3*2*1
OpenStudy (anonymous):
5 can't be correct; ABCDE, BCDEA, CDEAB, DEABC, EABCD, ACDEB, ...that's six combos right there and I know there are more
OpenStudy (cwrw238):
which is = 120
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OpenStudy (cwrw238):
no: 120 is correct
OpenStudy (anonymous):
I see
OpenStudy (anonymous):
Thank you
OpenStudy (cwrw238):
yw
OpenStudy (anonymous):
The reason why you get 5!, which is as cwrc correctly pointed out, is that you can select any of 5 for the first position, after which you have 4 to select for the 2nd position, after which ther are 3 for the 3rd, etc.
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OpenStudy (anonymous):
Thanks I had no idea ! Was a math symbol. Lol I just thought someone was super excited to answer 5