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OpenStudy (anonymous):
find the inverse of the function
(in comments)
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OpenStudy (anonymous):
\[g(x)= \frac{ 4 }{ x+1 }+2\]
OpenStudy (anonymous):
solve for x
x=(6-g)/(g-2)
that is inv of g(x)=6-x/x-2
asxis only a dummy variable to define the expression
OpenStudy (anonymous):
interchage x and y
OpenStudy (anonymous):
okay and then i subrtacted 2 from each side
OpenStudy (anonymous):
\[y=\frac{ 4 }{ x+1 }+2\]
\[x=\frac{ 4 }{ y+1 }+2\]
then solve for y
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OpenStudy (anonymous):
\[x-2=\frac{ 4 }{ y+1 }\]
\[y=\frac{ 4 }{ x-2}-1\]
OpenStudy (anonymous):
so far i got \[y+1=\frac{ 4 }{ x+2 }\] but i know it can be simplified more
OpenStudy (anonymous):
*x-2
OpenStudy (anonymous):
just subtract 1 both sides
OpenStudy (anonymous):
whenever you have to solve for an inverse function or to check the function is onto solve for the basic variable
hence i solved and got the answer
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OpenStudy (anonymous):
so final answer is \[y=\frac{ 4 }{ x-2 }-1\] @jim_thompson5910
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
divide the answer 6-x by x-2 you will get -1 as quottient and 4 as remainder which gives
-1+4/(x-2).the same asKatylon
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