1) Find the slope of the line through points (3, -5) and (2, -9). 2) Find the slope of the line through points (-10, 8) and (4, 6).
\[slope=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]It doesn't matter what coordinate you use as 1 or 2 as long as you stay consistent
\[(x_1,y_1)\]
I gave you the formula. All you have to do is plug in the numbers. I'll check your answers, but I'm not going to do it for you.
exactly as @ChmE says it. the slope/gradient formula is what he stated and you just plug in the values. (3,-5) (2,-9) (x1,y1) (x2,y2) now try it.
(3,2) (-5,-9)
>?
How did you do that? Try again.
\[\frac{ -9 - ? }{ 2-? }\]I started number 1 for you
-5/3 ??
nope, try again.
\[\frac{-9-(-5)}{2-3}\]= ????
-4/-1
which is 4.
now try to do the second one using the same type of procedure.
6+8/4-10?
@JayDS
(6-8)/(4+10)
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