find the inverse of the function (in comments)
\[f(n)=\frac{ -n+5 }{ 2 }\]
greatly would appreciate your help on this one @jim_thompson5910
i know i switch x and y
the first thing to do is to substitute f(n) for y
then switch n and y
then solve for y
care to show me the steps of solving for y
you get this part right \[\huge n = \frac{-y+5}2\]
?
yes
What you want to accomplish is y on one side of the equation and everything else on the other. A good first step is to get rid of that denominator 2. How would you do that?
multiply it so \[2x=-y+5\]
That's right. Could you work your way from here? Remember, your goal is to isolate y (make sure y is one side of the equation) NOTE: I mean y, not -y ;)
could you actually take me step by step, i am not quite sure that i understand what to do next.
Ok, we want to bring everything without y on the other side You have 2n = -y + 5 (yes, it's n, not x ;) ) First, you'll want to get rid of that +5 that is next to the y, how would you do that?
subtract it
Please demonstrate :)
\[2x-5=-y\] then you divide by -1 \[y=\frac{ 2x-5 }{ -1 }\]
Wow, that escalated quickly :D You've done well, now, what happens when you divide by -1?
hahaha c: uhhm you dont do anything, do you?
Well, actually, when you got to 2x - 5 = -y You divided both sides by -1, you could also multiply both sides by -1, it has the same effect, but it's easier to see the result. Just to be clear: \[\frac{k}{-1}=k \left( \frac{1}{-1} \right)=k \left( \frac{-1}{1} \right)=\frac{-k}{1}=-k\]
That said, now what can you say about \[y=\frac{ 2x-5 }{ -1 }\]?
hmm still not sure
Remember what happened to k when it was divided by -1? Refer to that which I posted.
y=-2x-5 ?
Please reconsider... :)
y=-2x+5
Yeah, sort of, just replace x with n
nope that's not it either
Of course that's not it, you started with n, you can't end up with x :P
it still isn't correct if it is n. if you plug in numbers for the variables, it doesn't appear to be the inverse
invof f=5-2x
How do you know? Can you give an example?
solve for n
You ended up with -2n + 5 Let's call that g(n) For a function f, g would be its inverse if f(g(n)) = n could you try that now?
2f=-n 2f-5=-n 5-2f=n
2f=-n+5 2f-5=-n 5-2f=n as n , are used for notations you can consider inverse of f(x)=5-2x
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