whats the lim x goes to infinity of 2/square root of x
0
yes
Rose if you're not convinced, just plug a large number into your calculator to check! :) if you plug one bajillion in for x, what value do you get for the limit? \[\frac{ 2 }{ \sqrt{bajillion} }\approx \frac{ 2 }{ 999999999 } \approx 0\]
yeah, but do what zepdrix said only for check, because if you do this in a test for example, it will be wrong because infinity is NOT a number...
okay
it is always 0 ?
no! it will depends on what you are taking the limit, always try to simplify the limit, try to do not have a denominator, in this case we can not simplify so we do this
i am trying to solve this problem where x goes to infinity 2+square root of x/ 2- square root of x
i am getting the answer as 1, is it right?
\[\lim_{x \rightarrow \infty}\frac{2+\sqrt{x}}{2-\sqrt{x}}\]
this one?
yes,
the limit is equal to -1
have you already study L'hospital rule ?
can you please explain how you got -1?
No,
ok let me explain
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