Determine the equation of the line tangent to the curve at the given point.
4x^2+3xy+4y^2=26; (2,1). help appreciated :D

Question

Determine the equation of the line tangent to the curve at the given point. 
4x^2+3xy+4y^2=26; (2,1). help appreciated :D

anonymous · Answer

i believe if you take the derivative of the equation and plug in your x and y values, you get the slope. then use the x and y to create a y-[y2]=m(x-[x2]) equation, where y2 = 1 and x2 = 2

anonymous · Answer

attachment

alexwee123 · Answer

@frankypoo you still there?

frankypoo · Answer

Yessirr

alexwee123 · Answer

do you still need help for this problem or did the previous comments answer your question>

alexwee123 · Answer

?*

frankypoo · Answer

well if their answers are correct then probably not aha.

frankypoo · Answer

But if you'd like to elaborate, it'd be much appreciated =)

alexwee123 · Answer

well there's not much to elaborate on since it's kind of straight forward....

frankypoo · Answer

oh

frankypoo · Answer

well I have two different answers up there^

alexwee123 · Answer

they're the same... the first one shows the procedure in finding the tangent line and @Zekarias solved it using that method i think :/ (it's kind of hard to discern the photo)

frankypoo · Answer

exactly aha

frankypoo · Answer

it's kinda blurry/sideways ;/

alexwee123 · Answer

ya :/
but you understand the procedure @chocokatlove gave you right?

frankypoo · Answer

Not exactly, :I

alexwee123 · Answer

hmm ok let's go through it step by step...
first of all find the derivative of the equation using implicit differentiation
can you do that for me and post your work here?

alexwee123 · Answer

argh nevermind i have to go soon so i'll just post the work here and hopefully you'll understand...

alexwee123 · Answer

so first find the derivative
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