A cone with a radius of 3" has a total area of 24π sq in. Find the volume of the cone.
Lateral surface area of cone = π r s Surface area of base of cone = π r² where s = slant height, r = 3 SA = π r s + π r²
put r =3 in above formula
@alli-rose Do it ?
um o.O i have noooo idea :/
what you dont know how to plug in a certain value ?
math is a terrible subject for me :/ im just trying to graduate and need help
Well,you have to participate ..
|dw:1350715080153:dw|
so SA = pi 3 s + pi \[3^{2}\] or something?
yeah right now see what is the s.a in your question ?
All you have to do is find the slant height . Using the radius and slant height find the height of the cone. Then plug those values to this equation to get the volume.. \[V = \frac{1}{3}*\pi r^{2}*h\]
@alli-rose
SA=Surface Area
ugh forget it -.- im so lost already thank you though
No Wait @alli-rose
See what is the totalarea in your question ?
\[SA= 3s π + 3^2π\]
First of all to calculate the slant height of the cone.|dw:1350754230467:dw|
Total surface area of a cone= \[3.14*radius ^{2} + 3.14*radius*slant height\]
You have the area and the radius but you don't have the slant height so, area=75.4 radius=3 slant height=h
75.4=\[3.14*3^{2} + 3.14*3*h\]
to find the volume, you use : V = 4/3 π r3(cubed) so... V = 4/3 π 3(cubed) V = 4/3 π 9 V = 36 π
so it would be 36 π in cubed .
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