Simplify sin^2(54)+cos^2(72)
Please don't just go sin 54 = blah and cos(72) = blah, so blah + blah = blahblah
@Callisto
is 54 the actual number or is that in 54 degrees?
54 degrees
So you just want to know how to computte this by hand?
yes
why did you go into radians?
so what is x equal to?
I fluttered that up ignore me.
Hopefully zrocker can help you X_X
\[sin^2(54)+cos^2(72)\]\[=(cos(90-54))^2+cos^2(72)\]\[=cos^2(36)+cos^2(72)\] That looks nicer
Oh, wait... let me try now
Okay :|
cos^2(36) + (2cos^2(36)-1)^2
am i right?
Yes.
now... do we evaluate cos(36) or simplify more?
Evaluate.
ok. is this straightforward or something we fancily work out?
very fancy :|
let x = 36 5x = 180 3x = 180 - 2x sin 3x = sin2x 3 sinx - 4sin^3 x = 2sinx cox Since sinx =/= 0 3- 4 sin^2 x = 2cosx 3- 4 ( 1-cos^2 x) = 2 cos x 4 cos^2 x - 2cosx -1 =0 Now, solve for cosx.
wow
@apple_pi Come back :'(
So in what class do we learn to play with this trick?
I'm sorry, I don't know. I'm not from the US. But for me, I learnt it two years before university.
Sorry... I had to go for a while
Yeah that solved it! Thanks @Callisto
You're welcome. FYI, this post is worth looking! http://openstudy.com/study#/updates/4fe6e718e4b02c91101b52cd
Got another one: http://openstudy.com/study#/updates/50827553e4b0dab2a5ebddaa
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