Question

Algebra help

Answer 1

When you multiply terms that have the same base you can add their exponents. When you divide terms that have the same base you can subtract their exponents

Answer 2

\[\frac{12f^6g}{16g^2} = \frac{ 2*2*3*f^6*g }{ 2*2*2*2*g^2 } = \frac{ 2^2*3*f^6*g }{ 2^4*g^2 } = 2^{2-4}*3*f^6*g^{1-2} = 2^{-2}*3*f^6*g^{-1} = \frac{ 3*f^6 }{ 2^2*g } = \frac{3*f^6}{4*g}\]

Answer 3

@Klaph , yours confused me

Answer 4

ya he over complicated it with all the 2*2*2 stuff. you can just see the 12/16 is 3/4. they are both divisible by 4. the f can't be reduced because there isnt an f in the denominator. the g can. because g^1/g^2 is the same as g^1-2 = g^-1 or 1/g

Answer 5

I'll make it a bit cleaner:
\[\frac{12f^6g}{16g^2}=\frac{2^2*3f^6g^1}{2^4g^2}= 2^{-2}*3f^6 g^{-1}=\frac{3f^6}{4g}\]

Hopefully it is easier to see what I mean. :-)