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X/x^2-4 - 1/ x+ 2 = 2
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\[\rm {x \over x^2 - 4} - {1 \over x + 2} = 2\]Factor the required stuff.\[\rm {x\over (x + 2)(x - 2)} - {1 \over x + 2} = 2\]Multiply -1/(x + 2)'s numerator and denominator by (x - 2)\[\rm {x \over (x + 2)(x - 2)}-{1 \over (x + 2)(x - 2)} = 2\]\[\rm {x - 1 \over (x + 2)(x - 2)} = 2\]
To clear out the fractions, multiply both sides by \(\rm x - 1 = 2(x + 2)(x - 2) \)
What do you mean by rm?
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