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Geometry 8 Online
OpenStudy (anonymous):

The figure below shows a circular prop with two triangles labeled ABC and AOC made on it. The center of the prop is labeled O. A circle is drawn with an inscribed triangle ABC. Angle ABC measures 45 degrees. O is the center of the circle. Triangle AOC has AC equal to 2 feet. What is the area of the cloth required to make the circular prop? 12.56 ft2 3.14 ft2 6.28 ft2 10.32 ft2

OpenStudy (anonymous):

OpenStudy (anonymous):

@CliffSedge help i posted a new question

OpenStudy (anonymous):

@CliffSedge

OpenStudy (anonymous):

So, it's asking for the area of the circle?

OpenStudy (anonymous):

@CliffSedge after u help me answer this one could we just post the next one on here plzzz cuz i have 57 more togo and i only have an houre to do them and posting them in new threads wastes my time

OpenStudy (anonymous):

i guess soo

OpenStudy (anonymous):

First of all, I am not going to help you with all 57. You really should be able to do most of them on your own. Anyway, to get the area of the circle, you can use the formula, A=πr^2, which means you need to find the length of the radius.

OpenStudy (anonymous):

its a pre test im in a normal class and they said anyone who could do this ap work would get extra credit and wouldent have homework that week except this and they said we can use what ever we need to

OpenStudy (anonymous):

OA and OC are both radii, so if you can find the length of them, you're in business. Here's how I would go about it: ABC and AOC are angles that cut the same arc, that means - by inscribed angle / central angle theorem - that AOC is twice the size as ABC. What does that imply?

OpenStudy (anonymous):

wouldent that mean that aoc is 90

OpenStudy (anonymous):

Correct. So you see that triangle AOC is a right triangle, and AC is the hypotenuse.

OpenStudy (anonymous):

yes soooo

OpenStudy (anonymous):

What can you use to find the lengths of the sides of a right triangle?

OpenStudy (anonymous):

a^2 +b^2=c^2

OpenStudy (anonymous):

am i right

OpenStudy (anonymous):

yep, Pythagorean Theorem to the rescue!

OpenStudy (anonymous):

but how do i find out what a and b r all i know is 2 ft

OpenStudy (anonymous):

As a general tip: any time you find a right angle, you should immediately write down the P.T. - it'll likely be useful. The two missing sides are radii of the same circle; it is an axiom that all radii of the same circle are congruent, so that is an isosceles right triangle. In other words, a=b.

OpenStudy (anonymous):

so 4+4=c^2 so c = 2.82

OpenStudy (anonymous):

Mmm, not quite. If c, the hypotenuse, = 2 feet, then you need r^2 + r^2 = 2^2

OpenStudy (anonymous):

thats comfusing so c=4 andi got to find out what a and b are

OpenStudy (anonymous):

No, c^2 = 4, and yes, a=b=r.

OpenStudy (anonymous):

so is C^2 = 4 the what am i gonna do

OpenStudy (anonymous):

Solve for r, using P.T. Or better yet, since you actually want r^2 to use in the area formula, just solve for r^2.

OpenStudy (anonymous):

Once you have r^2, multiply that by π, and you're all set. Looking at the answer choices, you don't need a value for π more accurate than 3.141

OpenStudy (anonymous):

SO THE AREA FORMULIA OF A TRIANGLE IS A=1/2BH

OpenStudy (anonymous):

.......

OpenStudy (anonymous):

....... is it

OpenStudy (anonymous):

Yes, . . . that is the area formula for a triangle, but I thought you were looking for the area of the circle.

OpenStudy (anonymous):

i am

OpenStudy (anonymous):

new question The figure below shows CB = 4, BE = 5, AB = 4x – 4, and DB = x + 3. Triangle ABC is a right triangle with measure of angle ACB equal to 90 degrees. The measure of side CB is 4 and AB is 4 multiplied by x minus 4. D is a point on the left of C on BC extended. A point E is labeled on AB such that DE is perpendicular to AB. Measure of EB is 5 and DB is x plus 3. If ?ABC ~ ?DBE, the value of x is _________

OpenStudy (anonymous):

could u helpme with this plzz

OpenStudy (anonymous):

Let me draw it out first...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

nvm ill post a pic

OpenStudy (anonymous):

OpenStudy (anonymous):

Ok, yeah, that was what I was imagining here. Alright, solving for x . . . You have similar triangles there, so AB : BD :: DE : AC :: BE : BC (corresponding sides are in equal proportion).

OpenStudy (anonymous):

AC : DE doesn't provide any info, so I'll throw those out, and you'll have the proportion, \[\large \frac{AB}{BD}=\frac{BC}{BE}\] Oops, I think I wrote the previous proportion wrong; should be AB : BD :: BC : BE, so it matches the above. Now plug in your given information and solve.

OpenStudy (anonymous):

is the answer 2

OpenStudy (anonymous):

.....

OpenStudy (anonymous):

Yep, that's what I got too.

OpenStudy (anonymous):

:P

OpenStudy (anonymous):

A city park has an architectural pillar in the shape of a triangular pyramid. The shape of the base of the pillar is an equilateral triangle. The dimensions of the shape of the pillar are as shown below. A triangular pyramid is shown. The shape of the base of the pyramid is an equilateral triangle having sides of length 2 feet. The lateral height is labeled as 14 ft. The park plans to repaint the lateral area of the pillar. The area of the pillar that will be repainted is _______________ ft2.

OpenStudy (anonymous):

OpenStudy (anonymous):

ummm i got 42 ami right

OpenStudy (anonymous):

I don't know. I already helped you with two questions, I think that is worth at least one medal. What do you think?

OpenStudy (anonymous):

i will if i get them right :P

OpenStudy (anonymous):

Bye then.

OpenStudy (anonymous):

dont goill give u a medal

OpenStudy (anonymous):

You really should close this and post a new question thread.

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