Question

pleaseee help, how can I simplify (- 2q^4/7)^4 ?

Answer 1

\[\frac{-2q^{16}}{7^4}\] Now solve..

Answer 2

That wouldn't be the answer?

Answer 3

Remember this rule..
\[(a^m)^n=a^{mn}\]

Answer 4

I'm so confused man.

Answer 5

??

Answer 6

Have you got any answers ?.

Answer 7

No... I'm really confused

Answer 8

According to the rule..
\[{(-2q^4)^4}\]

Answer 9

2q^16

Answer 10

-2q^16*

Answer 11

\[=-2q^{16}\]

Answer 12

yeah

Answer 13

Yeahhhh..

Answer 14

No what?

Answer 15

Now*

Answer 16

The denominator is also like that..

Answer 17

ok so -2q^16/7^4 but how do I solve that?

Answer 18

so i think first of all you need deciding 7 is denominator of exponent or ????

Answer 19

What do you mean?

Answer 20

-2q^4
(------ )^4
7

so hence will be right or how ????

Answer 21

It's not even an answer choice in my question.
-2q^4/7 is

Answer 22

I mean -2q^16/7

Answer 23

so than sign that 7 will be the indice of radical

yes ?

Answer 24

I have no idea what you're talking about.

Answer 25

so this is because x^(1/2) =sqrt(x)

so 2 is indice of radical

ok ?

Answer 26

@Miyuru do you understand it ?