dalta x =vi+a(dalta t _1\2) who can proof it

Question

anonymous · Answer

Is this equation right? Use the equation writer to make it better to read.

anonymous · Answer

Equation so it's easier to read:

$$\Delta x =vi+a(\frac{\Delta t _1}{2})$$

anonymous · Answer

A proper 'proof' of this will probably require calculus.

However, did you know that the area under the line $v=at$ is the same as the distance? So using the formula for a triangle, you can find $\Delta x = a(\Delta t^2/2) + some\_constant$ That some constant is $v_i$, which you have to provide.

Kinda hard to explain.

anonymous · Answer

@muntoo is right, but the equation you gave is wrong then, because delta t is not squared