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double integral help
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\[\int\limits_{0}^{1} \int\limits_{0}^{1} x^2e^(xy) dy dx\]
that should be e^(xy)
keep x as constant and y as a variable and integrate.
right
use u=xy, then \[\frac{\partial u}{\partial y}=x\implies du=xdy\]so\[\int_0^1\int_0^1x^2e^{xy}dydx=\int_0^1\int_0^1x(e^{xy}xdy)dx\]
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si i get (x^2e^(xy))/x which gives me xe^(xy)
@m.auld64 yaa ur right ... proceed
well then do i need to do integration by parts?
after that substitute the limits and then go for integration by parts..
right which would give me xe^x-x dx but how do i do my by parts with three terms
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