Question

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Answer 1

number of terms =5
n=5

first point = -3

depending on starting point, lets say n=1

then the equation to get any point would be n-4

stuff it all together
\[\sum_{n=1}^{5}n-4\]

Answer 2

What's your initial value? (Hint: there are two, but I would probably use the smaller one.)

How many numbers are there?

Answer 3

there are a thousand ways you could write the summation, depending on what n value you want to start with

Answer 4

so the answer is sigma (n = 1 to 5) of n-4

Answer 5

i think, i might be wrong, i rarely have to use sigma notation, and when i do, its usually to infinity

Answer 6

Yeah because the sum is equal to -5..but the answer to the sequence is 1?

Answer 7

@completeidiot Aha, that's right. (n-b), b is of the set of integers and all that. :)

Answer 8

the question isnt asking for the sum, its just asking for the sigma notation

and the sum is equal to -5, where did you get 1?

Answer 9

\[\sum_{n=-3}^{1}n\]

Answer 10

n*

Answer 11

Did you see how n starts at -3, and stops when it equals to 1?

Google "sigma notation".