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ind a possible formula for the 4th degree polynomial g satsfying the following properties. g has a double zero at X=3; g(5)=0, g(-1)=0, and g(0)=3. You may leave your answer in factored form
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\[g(x)=(x-3)^2(x-b)(x-c)\]
\[g(x)=a(x-3)^2)(x-5)(x+1)\]
get a (0,3) \[3=a(0-3)^2(0-5)(0+1)\]
Is that my ans?
no \[g(x)=\frac{ 1 }{ 15 }(x-3)^2(x-5)(x+1)\]
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