Question

find the derivative of y= xsec kx

Answer 1

use chain rule along with product rule.
\[ \frac{d}{dx}(xsec(kx))=\frac{d}{dx}(x)\sec(kx)+\frac{d}{dx}(\sec(kx))*x\]
where
\[\Large \frac{d}{dx}(x)=1\]
\[\Large \frac{d}{dx} (\sec(kx))=ksec(kx)\tan(kx)\]
can you do this now ?

Answer 2

yeah i think i go it