Question

help please
what the equation of tangent line a curve x^3+2x^2+1
absis=1

Answer 1

Find the equation of the tangent line to the curve\[y =x ^{3}+2x ^{2}+1\]Is this your question?

Answer 2

at x = 1?

Answer 3

To find the equation of a tangent to a curve y = f(x) at x = a:

i). Find y when x = a. In other words, find f(a) so that you have the point (a, f(a))
ii). Evaluate the derivative (slope of a tangent) at x = a.
iii). Use the slope from step ii) and the point (a, f(a)) from step i) to find the equation of the tangent y = mx + b.

Answer 4

y=x^3+2x^2+1
at x=1
y=1+2+1
y=4
slope
dy/dx=3x^2+2x
at x=1
dy/dx=3+2=5
slope=5
equat of tangent
y-4=5(x-1)