Chemistry
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OpenStudy (mayankdevnani):
How many electrons are present in 1.6 g of methane?
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OpenStudy (mayankdevnani):
@amriju @heena @ParthKohli @hartnn @.Sam.
OpenStudy (anonymous):
first do this step
n(mole)=mass/molecular weight
OpenStudy (mayankdevnani):
ok
OpenStudy (mayankdevnani):
methane= \[CH_{4}\]
OpenStudy (mayankdevnani):
right @heena
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OpenStudy (anonymous):
ya
OpenStudy (mayankdevnani):
so gram molecular mass=12+4=16g
OpenStudy (mayankdevnani):
right
OpenStudy (anonymous):
ya
OpenStudy (mayankdevnani):
but what is the realtion of electrons in mole
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OpenStudy (anonymous):
i already given u the formula put value when u ll get n den
n=electron/avogadro num
OpenStudy (mayankdevnani):
ok
OpenStudy (anonymous):
nw solve and show me ur ans
OpenStudy (mayankdevnani):
so no. of moles in 1.6g of methane=1.6/16=0.1
OpenStudy (mayankdevnani):
right
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OpenStudy (mayankdevnani):
@heena
OpenStudy (mayankdevnani):
@Callisto @UnkleRhaukus @estudier
OpenStudy (anonymous):
do the work den i ll tell whether u are right or not
OpenStudy (mayankdevnani):
no. of moles of methane in 0.1 mole=0.1*6.022*10^23=6.022*10^22
OpenStudy (mayankdevnani):
right
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OpenStudy (mayankdevnani):
one molecule of methane has=6+4=10 electrons
OpenStudy (anonymous):
ye u did it ^.^
OpenStudy (mayankdevnani):
it is the power
OpenStudy (anonymous):
yea ne multiply u an wid 4
OpenStudy (mayankdevnani):
@heena one molecule of methane has=6+4=10 electrons
i don't understand this line
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OpenStudy (anonymous):
see c num.-->6 outermoct electron it is nt in ur coure yet
H4 num. --->4
OpenStudy (mayankdevnani):
ok thnx @heena