Question

(x^2 - x -2)^3
how to solve this equation

Answer 1

Equation?

Answer 2

an equation has an equal sign

Answer 3

ok y=(x^2-x-2)^3

Answer 4

lol do you have to solve for \(\rm x\)?

Answer 5

i need the roots

Answer 6

factorise what is in the brackets

Answer 7

To find the roots, you have to find the value of x where the function is 0.\[\Huge \rm (x^2 - x - 2)^3 = 0\]

Answer 8

what next

Answer 9

Find the cube root of both sides.
Solve the quadratic equation.

Answer 10

k thnx

Answer 11

(x^2-x-2)^3
(x^2-2x+x-2)^3
(x(x-2)+1(x-2))^3
(x+1)^3 .(x-2)^3

Answer 12

So what do you get?

Answer 13

same as nitz

Answer 14

thnx nitz

Answer 15

That's not what I told you. lol

Answer 16

i was jst unsure whether to open the brackets or not !!

Answer 17

Well, it's OK. Her method works too!

Answer 18

hahaha..yea it does

Answer 19

thnx again

Answer 20

\[y=(x^2-x-2)^3\]\[0=(x^2-x-2)^3\]\[0=\left((x+1)(x-2)\right)^3\]\[0=(x+1)(x-2)\]
\[x=-1,2\]