Find the magnitude and direction (relative to the x axis) of the acceleration of the object.
F1=40.0N due east
F2=60.0N 45.0 degrees North of east
M=3.0kg

Question

Find the magnitude and direction (relative to the x axis) of the acceleration of the object.
F1=40.0N   due east
F2=60.0N   45.0 degrees North of east
M=3.0kg

anonymous · Answer

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Resolve $F_2$ into $F_{2x}$ and $F_{2y}$ first,

anonymous · Answer

Im not sure I understand. But I have F2x = 42    and     F2y = 42

anonymous · Answer

$$F_{2x}=F_2\cos40\F_{2y}=F_2\sin40$$

anonymous · Answer

sorry, it's 45 :D my drawing's wrong too. It should be 45 degrees.

anonymous · Answer

It must have the same value, since sin 45 = cos 45.

anonymous · Answer

But for just F2 alone its 42 for both

anonymous · Answer

the answer is 93 I just cant see how to get it

anonymous · Answer

I got 92.7 using the same method.

anonymous · Answer

what method!

anonymous · Answer

how do I get that answer! :)

anonymous · Answer

1) Find total force in x
2) Find total force in y
3) Find the 'grand' total force $F=\sqrt{F_x^2+F_y^2}$

anonymous · Answer

actually the answer is 30.9 m/s 2, 27.2 above the x axis

anonymous · Answer

yes, that's 92.7 N/3 kg.