A loaded die is such that when it is thrown the probability of obtaining a score of six is 0.25. In 5 throws of the die calculate the probability that: (I) a six will be obtained for the first time on the last throw. B) what is the probability that the 5th six occurs on the 15th trial?
Looks like a negative binomial situation. Do you know the formula for that?
Can really be done just using multiplication rule, though.
For part (B), you'll first want to calculate the probability of getting 4 sixes in 14 trials.
First part I've sorted now :) So for part B once you've worked out the probability of getting 4 sixes in 14 trials do you add it to the probability of getting one 1 six on the 15th trial?
No, just multiply it by the probability of getting a six one more time.
Awww that's great - thanks for your help :)
Join our real-time social learning platform and learn together with your friends!