Question

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Answer 1

Okay, this one is a lot more interesting =)

Answer 2

So here's the process.
1) Graph all 4 of those constraint inequalities.
2) Look at the shape that it makes and notice where the vertices are.
3) For each of the vertices, plug the coordinates into your C= equation.

Answer 3

So let's start with the graphing step.

Answer 4

I gave you some axis =)
Start with the easy ones. Graph x>0
and y>0

Answer 5

Do you know how to graph the line x=0?

Answer 6

x = 0 is the line where all of the points have an x value of 0, but any different y value you can think of.

Answer 7

(0,1) (0,2) (0,3) (0,10) (0,100000) (0, -80) are all points on the line x=0

Answer 8

Yes =) Exactly. That's the line x=0, and the portion we're talking about with x>0 would be

Answer 9

Everything to the right of that.

Answer 10

How about y>0?

Answer 11

Good =) And y>0 is above that line.
Now, graph 4x +3y>30
It would probably be helpful to put it into y = mx + b form first.

Answer 12

Correct =) Now graph those.

Answer 13

hmph

Answer 14

You know about the y-intercept, right? You can plot that point.

Answer 15

You need to know how to graph them!

Answer 16

Okay, if it's in y = mx + b form, then the b part is the y-intercept. Just look at what that number is and find it on the y axis. That is your first point.

Answer 17

Once you have that point, look at the slope. Slope is rise over run, so you can use that to get more points.

Answer 18

Looks good =) And which direction should we shade? Since it's y>

Answer 19

mmm I actually disagree

Answer 20

Y>
for both of those lines, so we need to shade ABOVE for both lines.

Answer 21

Where is the region we are talking about then?

Answer 22

Exactly =)

Answer 23

So now we have to find the vetices (corners) of that region. There are 3 of them.

Answer 24

vertices*