Question

How do i differentiate this and find the gradient at point x=2

Answer 1

\[y = \frac{4}{3x-4}\]

Answer 2

@Callisto @precal @SmoothMath

Answer 3

@ParthKohli

Answer 4

\[(\frac{ f }{ g })^ '=\frac{ f^'g-fg^' }{ g^2 }\]

Answer 5

qutient rule

Answer 6

\[f=4,g=3x-4\]

Answer 7

i dont understnd

Answer 8

\[f^'=0,g^'=3\]
so just plug in

Answer 9

@satellite73 @Pallavi06 @SmoothMath @experimentX

Answer 10

\[\frac{ dy }{ dx }=\frac{ 0(3x-4) -3(4)}{ (3x-4)^2 }=\frac{ -12 }{ (3x-4)^2 }\]

Answer 11

\[\frac{ -12 }{ (3(2)-4)^2 }=-3\]

Answer 12

aren't there any easy methd?

Answer 13

no........this is the method..........

Answer 14

\[4(3x-4)^{-2}\]
how do i do this now

Answer 15

u have to differentiate it??

Answer 16

yh

Answer 17

wht is chain rule

Answer 18

\[\frac{ dy }{ dx }=\frac{dz }{ dx }\frac{ dy }{ dz }\]

Answer 19

\[\frac{ 4 }{ 3x-4 }=4(3x-4)^{-1}\]
let\[z=3x-4\]
\[\frac{dz}{dt}=3\]
\[y=4z^{-1}\]
\[\frac{ dy }{ dz}=-4z^{-2}\]

Answer 20

\[\frac{ dy }{ dx }=?\]

Answer 21

\[3(-4z^{-2})=-12(3x-4)^{-2}\]