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When heated, KClO3 decomposes into KCl and O2. If this reaction produced 88.4 g of KCl, how much O2 was produced (in grams)? 2KClO_3--->2KCl+3O_2 2(KClO_3)=245.096 , 2KCl=149.102g, 3O_2=95.994
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convert 88.4g of KCl to moles divide by 2 and multiply by 3, convert the moles to grams of O2
The only formula you need to solve this is \[Mole = \frac{Grams}{MolecularMass}\]
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