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OpenStudy (anonymous):
What is the normal force on the box?
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OpenStudy (anonymous):
A person pushes on a stationary 125 box with 63 at 30 below the horizontal, as shown in the figure. The coefficient of static friction between the box and the horizontal floor is 1.05.
OpenStudy (anonymous):
N=125+63sin30
OpenStudy (anonymous):
THANK YOU!!! That makes so much sense!
OpenStudy (anonymous):
Is there any way you could help me with finding the frictional force on the box?
OpenStudy (anonymous):
the frictional force is the normal force times the coefficient of friction...
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OpenStudy (anonymous):
ah so the normal force was 157 N... how do we find the coefficient of friction?
OpenStudy (anonymous):
It's given
OpenStudy (anonymous):
157 x 1.05 doesn't seem to be working... thats okay though.. thank you for your help!
OpenStudy (anonymous):
I doubt the value of 1.05 is correct... you should check it. coefficients of friction are usually not greater than 1
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