What is the normal force on the box?

Question

anonymous · Answer

A person pushes on a stationary 125  box with 63 at 30 below the horizontal, as shown in the figure. The coefficient of static friction between the box and the horizontal floor is 1.05.

anonymous · Answer

N=125+63sin30

anonymous · Answer

THANK YOU!!! That makes so much sense!

anonymous · Answer

Is there any way you could help me with finding the frictional force on the box?

anonymous · Answer

the frictional force is the normal force times the coefficient of friction...

anonymous · Answer

ah so the normal force was 157 N... how do we find the coefficient of friction?

anonymous · Answer

It's given

anonymous · Answer

157 x 1.05 doesn't seem to be working... thats okay though.. thank you for your help!

anonymous · Answer

I doubt the value of 1.05 is correct... you should check it.  coefficients of friction are usually not greater than 1