Question

if x^2/36 +y^2/16 and y(1)=3.94405 find y'(1) by implicit differentiation.

Answer 1

sorry, if x^2/36 +y^2/16 = something?

Answer 2

opps if x^2/36 +y^2/16 =1

Answer 3

ok. so
x/13+yy'/8=0
plug in 1 for x and 3.94405 for y
1/13+(3.94405/8)y'=0
y'(1)=-(1/13)(8/3.94405)

Answer 4

2x/36 + (2y/16)y' = 0
next sub in values

-2x(16)/36(2y) = y'

-2(1)(16)/( 36(2)(3.94405) ) = y'

Answer 5

so what will the answer equal?

Answer 6

https://www.wolframalpha.com/input/?i=-2%281%29%2816%29%2F%28+36%282%29%283.94405%29+%29&dataset=

Answer 7

There is your answer, I hope you understand this material

Answer 8

thank you, and yes im starting to get the hang of it