Question

cube root of 56x14

Answer 1

Can you find the Prime Factorization?

56*14 = 56 * 7 * 2

That's just a start. You chop up 56 until you have ONLY Prime Numbers showing.

Answer 2

x is a variable

Answer 3

\[\sqrt[3]{56x^{14}}\] that?

Answer 4

\[\Large{\sqrt[3]{56\times14}=\sqrt[3]{2\times2\times2\times7\times7\times2}=2\sqrt[3]{98}}\]

Answer 5

what are the steps

Answer 6

i need help

Answer 7

No one can help you until you confirm what the actual problem statement is. TheViper gave a good demonstration of the solution if the problem is as stated there. Right above that, I provided anoither choice. What is the problem statement?

Answer 8

Step1- First find the factors of 56 &14

Answer 9

it is the one you said

Answer 10

x is to the power of 14

Answer 11

cuberoot(56) = cuberoot(7*(2^3)) = cuberoot(7)*cuberoot(2^3) = cuberoot(7)*2

cuberoot(x^14) = cuberoot((x^12)*(x^2)) = (x^4)*cuberoot(x^2)

Answer 12

can you show me that with the symbols?

Answer 13

It won't be any different.

\[\sqrt[3]{56} = \sqrt[3]{7\cdot 2^{3}} = \sqrt[3]{7}\cdot \sqrt[3]{2^{3}} = \sqrt[3]{7}\cdot 2\]
\[\sqrt[3]{x^{14}} = \sqrt[3]{x^{12}\cdot x^{2}} = \sqrt[3]{x^{12}}\cdot \sqrt[3]{x^{2}} = x^{4}\cdot \sqrt[3]{x^{2}}\]

Answer 14

what is the final answer

Answer 15

You can't make me do all the work. You tell me the finalk answer. Demonstrate some ability to solve such problems or I'm going to have to start thinking that you are not attending class.

Answer 16

the way you explained it made me so confused

Answer 17

can you show me the steps one by one?

Answer 18

I did that, already. Now, you need to take one last step by yourself or this discussion is of no value.