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Mathematics 15 Online
OpenStudy (lgbasallote):

How do you compute for the range of a function? is it just the inverse?

OpenStudy (baldymcgee6):

The domain of the original function will be the range of the inverse.

OpenStudy (baldymcgee6):

I don't think there is ALWAYS a systematic way of computing the range; as opposed to always having a systematic way of computing the domain.

OpenStudy (lgbasallote):

and the range of the original function would be the domain of the inverse?

OpenStudy (baldymcgee6):

Right, as well as all point (x,y) in the original become (y,x) in the inverse

OpenStudy (lgbasallote):

this is getting confusing....

OpenStudy (lgbasallote):

what is the range without looping words?

OpenStudy (baldymcgee6):

What do you mean, "without looping words"?

OpenStudy (lgbasallote):

well you're using words that loop (and make it complicated)

OpenStudy (lgbasallote):

domain of function is the range of the inverse and the range of the function is the domain of the inverse where (x,y) is (y,x) in inverse ^see how loop-y that is?

OpenStudy (lgbasallote):

do you know a simple explanation @nincompoop ?

OpenStudy (baldymcgee6):

Sorry, simply put: the range of a function is all the values of the dependent variable for which the function is defined. Eg: y = x^2 The range is all the values for which the dependent variable (y) is defined, which is all values greater than zero. You will never get an output of a negative number from this function.

OpenStudy (lgbasallote):

so....the range *is* the domain of the inverse function?

OpenStudy (baldymcgee6):

Yes, the range of the original function IS the domain of it's inverse.

OpenStudy (lgbasallote):

please say yes or no before going into very confusing details

OpenStudy (lgbasallote):

ahh a yes then

OpenStudy (lgbasallote):

it was all i wanted to hear....

OpenStudy (baldymcgee6):

|dw:1350876020195:dw|See how the Domain and range simply switch. As you can see, the inverse of a function is reflected along y=x

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