If limx> a[f(x)+g(x)] = 2 and lim x>a [f(x)-g(x)] = 1. Find lim x>a [f(x)g(x)].
Do you know the properties of limits?
Yes. But I'm confused what to do with this question.
\[\lim_{x \rightarrow a}[f(x)+g(x)]=\lim_{x \rightarrow a}f(x)+\lim_{x \rightarrow a}g(x)\] \[\lim_{x \rightarrow a}[f(x)-g(x)]=\lim_{x \rightarrow a}f(x)-\lim_{x \rightarrow a}g(x)\] \[\lim_{x \rightarrow a}[f(x)g(x)]=\lim_{x \rightarrow a}f(x)∙\lim_{x \rightarrow a}g(x)\] There are of course more properties but these are the three you need to solve this problem.
Do you want a hint?
Yes please!
Sorry about that. I was typing and the stupid server keeps resetting. Give me a second to type it again.
It's okay! Yea the server has been very glitch today ):
Hint: Let\[\lim_{x \rightarrow a}f(x)=m\]and\[\lim_{x \rightarrow a}g(x)=n\]Do you understand what to do next?
I think so.... i will retry the question. Thank you very much!
I'll wait. Show me your work.
Can you show me the next step using this hint and the properties of limits?
\[\lim_{x \rightarrow a} f(x) = \lim_{x \rightarrow a} (\frac{ 1 }{ 2 } [f(x)+g(x)] - [\frac{ 1 }{ 2 } f(x)-g(x)]\]
sorry the minus between the two functions is suppose to be a plus*
No, I meant that\[\lim_{x \rightarrow a}f(x)+\lim_{x \rightarrow a}g(x)=2\]m + n = 2 (equation 1)\[\lim_{x \rightarrow a}f(x)-\lim_{x \rightarrow a}g(x)=1\]m - n = 1 (equation 2) Now solve for m and n first. What do you get?
n=1/2 & m=5/2*
Yes m = 1/2 but n is incorrect. Please try again.
Sorry for a delay in responding but some idiot keeps harassing by sending me improper messages.
It's okay. Is there no option to block them?
I reported him so let's see if they do anything about it.
is m = 3/2?
Yes sorry I meant m = 3/2 and n = 1/2. Sorry I'm trying to focus but this person just doesn't stop.
Beset thing to do is not reply to him cause you're just feeding him to go on and on.
You're absolutely right.
So do you know the next step?
would you use the third limit property (from above) and multiply the two?
Actually the final answer now that you have solved the individual limits.
Yes! Go ahead.
Therefore the product of these limits is?
3/4
Beautiful!! Excellent work!! So do you now understand the concept of solving these types of problems?
Yes, I do. thank you very much!! My prof explained it very complicated... so I didn't really understand it. Really appreciate the help!
Absolutely any time! I have to log out now. That's what I said after helping the last person as well LOL but I really do have to go. I'll be back in a few hours maybe, so if you need me thensimply message me and I will definitely help you as soon I get back. Take care!
LOL don't worry that happens to everyone. Thanks once again!!! (:
Welcome! Bye for now!
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