Question

cube root of 56x14

Answer 1

i want to know the steps

Answer 2

x is to the power of 14

Answer 3

you need to look for portions of "56" and x^14 that can be expressed as some term cubed.

So, for example, if you had x^4, you could express it as x^3 * x... and then the cube root would be "x cube root of x"
\[\sqrt[3]{x ^{4}} = \sqrt[3]{x ^{3}x} = (\sqrt[3]{x ^{3}})(\sqrt[3]{x}) = x \sqrt[^{3}]{x}\]

Answer 4

portions of 56 would be 2 and 7?

Answer 5

If you have x^14, that is the same as x^3 * x^3 * x*3 * x*3 * x^2... so the cube root will pull out an "x" from each of the "x^3" terms, leaving x^2 under the cube root.

Answer 6

56 works out to 2*2*2 * 7
56 = 8 * 7
= 2^3 * 7

so cube root of 56 is "2 cube root of 7"\[\sqrt[3]{56} = \sqrt[3]{8 \times 7} = \sqrt[3]{2^{3}\times 7} = \sqrt[3]{2^{3}}\sqrt[3]{7} = 2\sqrt[3]{7}\]

Answer 7

oh i get it

Answer 8

can you show me cube root of x in symbols?

Answer 9

what do you mean? Sorry, glad to help but I don't understand what you're asking.