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Mathematics 13 Online
OpenStudy (anonymous):

Find the derivative of y=cos3x^2 & y=(cos3)x^2. explain without chain rule ?

OpenStudy (lgbasallote):

do you mean \[\huge y = \cos^3 (x^2)\]

OpenStudy (anonymous):

\[y=\cos 3x ^{2}\]

OpenStudy (anonymous):

Can you clarify a bit more, @distinction ?

OpenStudy (anonymous):

the derivative, as in y= 5+sin x --> y'=cos x or y =xcosx ---> y'= cosx-sinx

OpenStudy (anonymous):

I know what a derivative is, and if y = x*cos(x), then y' = cos(x) - x*sin(x) . . . What do you mean by "explain without chain rule?"

OpenStudy (anonymous):

i didnt learn how to use the chain rule yet.. so i wanted to know how to find the derivative without applying it.

OpenStudy (anonymous):

Perhaps u can do it from first principles (x to x+h etc), think u may just as well wait for the chain rule though...

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