Question

A cone with height 4 cm and diameter 4 cm contains water that has a depth of h cm, but the water is dripping out a rate of 1/2 cm^3/s. How fast is the depth of the water decreasing when the depth of the water is 2cm?

Answer 1

If you're going to reply to this question, thank you in advance! But I need to go to sleep for now. I'll come back to it when I wake up.

Answer 2

opinion ?

Answer 3

so if the diameter is 4 cm than how many will be the radius of the base ?
after you know it you need to calcule the volum of the cone,hope you know formula for V .


so from your words i understand that the water has a depth of h what is equal with the height of cone ,yes ?

Answer 4

h why equal r so when h=4 and r=2 ?

Answer 5

yes so r=h/2

Answer 6

so ok but where is your answer in secoundum what was the question ?

Answer 7

dont understand your question

Answer 8

so when r=h/2
dh/dt=-1/2pi cm^3/s

Answer 9

how can being this minus ?

Answer 10

the rate is decreasing

Answer 11

so in the text of exercise is without minus and without pi ,check it please

yes ?

Answer 12

could be

Answer 13

so and what will be your final answer for this last question ?

Answer 14

-1/2pi = -1.57

Answer 15

this is the time in secoundum like the answer on the last question of this exercise ?

Answer 16

what does secoundum mean?

Answer 17

this wann to be seconde

Answer 18

sorry

Answer 19

ok ?

Answer 20

do you mean the units of the answer?

Answer 21

1.57cm^3/s

Answer 22

ok i accept it but depend what choises has Eric in mathbook

bye

Answer 23

bye