Question

If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.

x – 3y – 3z = –13
x + 2y – z = –1
2x + 3y + 2z = 0

Answer 1

x – 3y – 3z = –13
(x + 2y – z = –1)*3
***************
x – 3y – 3z = –13
3x + 6y – 3z = –3
----------------------subtract
(x-3x) + (-3y-6y) + (-3z - -3z) = (-13- -3)
-2x -9y + 0z = -10
-2x - 9y = -10

now you try the second and third equations

Answer 2

I'm so lost right now!

Answer 3

why, what dont you understand?

Answer 4

hmmmmmmm................EVERYTHING that has to do with math!

Answer 5

lol why? math is easy and sweet lol

Answer 6

worst subject for me

Answer 7

what grade are you in?

Answer 8

11th

Answer 9

you will have to multiply one or two of the equations with numbers so when you add or subtract them one of the terms drop

in equation 1 and 2 you needed to drop z
1st eq had -3z
2nd eq had -z
in order to drop that term we need to multiply the 2nd eq by 3