Solve the system by graphing. -5x-y=-11 2x-y=10
@Algebraic! can you help me?
Do you know how you can graph a straight line?
Because this is the only thing that you have to do here. Graph 2 lines, find the intersection and abracadabra you are done.
I can't get them into slope intercept form....
-5x-y=-11 2x-y=10 You want them in y= somthing form For the first one if you add y to both sides and 11 you get -5x-y+y+11=-11+y+11 that is -5x+11=y or y=-5x+11
Also for graphing you only need to find 2 points and connect them. -5x-y=-11 If x=0 -y=-11 so y=11 (0,11) is on the line If y=0 -5x=-11 so x=11/5 (11/5,0) is on the line too. Plot these two points and connect them so you have your line. Same with the other equation
This was no help at all....
I showed you 2 ways of doing this problem.
I have to tell where the two lines intersect and they don't at all..
Well they should, if they dont intersect than they are parallel, but these two are not.
Where do they intersect? Because I did the problem three times and I can't see where they did..
a, -5x-y=-11 b, 2x-y=10 I already expressed a, that was y=-5x+11 b, is y=2x-10 At x=0 a, takes y=11 b, takes y=-10 Now a, has a slope of -5 and b, has a slope of +2. So you can see that they have to meet at one point
If you solve these equations you get the intersection. It will be at x=3, y=-4
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