Help Calc!
\[ w = \sqrt{(x ^{2} * 5^{x}})^{3}\]
so there are w=sqrt(x^2 *5^x)^3 yes ?
so this you need to si,plifie it ?
simplifie it ?
so i think will help you if you know how you can writing the squarroot using exponent do you know it ?
i need to use chain rule to find the derivative of the function
\[w=\sqrt{(x^2*5^x)^3}=[(x^2*5^x)^{3}]^{1/2}=(x^2*5^x)^{3/2}\] It might help you to differentiate it easier if you rewrite the square root as a fractional exponent. From here you'll take the derivative starting from the outermost function, applying the power rule to that exponent.
well the answer is \[3/2x ^{2}\sqrt{5^{3x}}(2+x \ln 5)\]
I am stuck on w'(x) = \[1/2(x ^{2}*5^{x})^{3} * 3 (x ^{2} *5^{x})^{2} * 2x (\ln5) 5^{x}\]
you really should combine those powers before you apply the derivative, don't do the square root THEN the cube .. change it a 3/2 power. Also, part of the trouble you're running into is, you're forgetting that the INNER function is the product of 2 terms involving x. So you'll need to apply the product rule for that inside part! <:D
can you break it down for me :/
|dw:1350939516556:dw| Ok this is where we want to start, we want to simplify it nice n pretty like this before we attempt to take a derivative.
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